Question

Question #f6476

Answer 1

There are 7 atoms of C in one molecule of the compound.

This is sort of like an empirical formula problem.

Assume you have 92 g (1 mol) of the compound.

Then you have

92 g Compound × `(91.41" g C")/(100" g Compound")` = 84 g of C.

Moles of C = 84 g C × `(1" mol C")/(12.01" g C")` = 7.0 mol C ≈ 7 mol C

1 mol of Compound contains 7 mol of C

∴ 1 molecule of Compound contains 7 atoms of C.

Hope this helps.