Question #cb003

1 Answer

Yes, this is the #TiO_2# is the correct formula for Titanium (IV) oxide.

The roman numeral IV means the titanium forms a cation with a +4 charge by losing 4 electrons.

The oxygen atoms gain two electrons and form an anion with a -2 charge.

The ratio for the elements in the compound must be 1:2 because titanium gives up 4 electrons and each oxygen can accept two electrons.