Question

Question #a926e

Answer 1

I will assume you mean a volume of 10 `cm^3` of methane when answering this question.

There is a long way and a short way to answer this.

Here is the short way:
1 mole of `CH_4` will produce one mole of `CO_2`, think about it both molecules have 1 carbon atom, so it must be a 1:1 ratio. No need to balance an equation to see that, right?

Since the volume of two different gases (same number of particles) will be the same at STP conditions (1 mole of methane would be 22.4L and 1 mole of carbon dioxide would also be 22.4 L).

The answer must be a volume of 10 `cm^3` of `CO_2` will be produced.

Notice how there is no need to balance the equation or to determine the number of moles or mass of carbon dioxide produced.

Now, if the question is more specific and asks for those types of details, you would need to carry out a stoichiometric calculation.