Question

Question #7f520

Answer 1

You add the bond energies of the individual bonds.

Explanation:

The structure of glucose is

The molecule contains 5 `"C-C"` bonds, 7 `"C-H"` bonds, 7 `"C-O"` bonds, and 5 `"O-H"` bonds.

`D("glucose") = 5D("C-C") + 7D("C-H") + 7D("C-O") + 5D("O-H")`
`D"/kJ·mol"^"-1": color(white)(mm)347color(white)(mmmm) 413color(white)(mmmmm) 358color(white)(mmmm) 467`

`D("glucose") = (5×347 + 7×413 + 7×358 + 5×467) color(white)(l)"kJ" = "9467 kJ"`

∴ The bond energy of 1 mol of glucose is 9467 kJ.