Question edd2c

1 Answer
Dec 26, 2014

The answer is $25 m L$.

I've done a little research and discovered that, for mannitol (a sugar alcohol derived from the sugar manose by reduction) solutions, the concentration is usually w/v.

A w/v solution is used when a substance is mixed as a dry mass (grams) per mL (volume):

"w/v%" = (mass)/(volume) * 100%

So, a 20% w/v solution would have 20.0 g of mannitol for every 100 mL of solution -> 20g/100mL . Therefore, the volume needed for 5.0 g of mannitol is

"w/v%" = (mass)/(volume) * 100 -> volume = (mass * 100)/("w/v%")#

$v o l u m e = \frac{5.0 \cdot 100}{\left(20 \text{g/100mL}\right)} = 25 m L$