What is the hybridization of PF5?

1 Answer

the hybridization of #PF_5# is # sp^3d# .

In #PF_5# , the valence electrons of phosphorus are 5.
and we take the oxidation state of halogens as 1.

So, for one F , electron is 1 and for #F_5# the no. of electrons is 5.

therefore, (from phosphorus and fluorine)

5-5=0 electrons = 0 lone pairs.

there are 5 sigma bonds in this compound.

So, 5 sigma bonds + 0 lone pairs = 5. #-># #sp^3d#

hence , the hybridization of this compound is #sp^3d# .

Note:-

2 has sp hybridization.
3 has #sp^2# hybridization.
4 has #sp^3# hybridization.
5 has #sp^3d# hybridization.
6 has #sp^3d^2#