Question #f8d17

1 Answer
Sep 5, 2014

First of all, you have put this question in the wrong section. The answer for the domain is #x in RR# for #f(x)=(x-4)^(1/3)#.

This is a different case than #f(x)=sqrt(x-4)# because a real number times itself can never be negative, eg. #x*x!=-2#. This is always the case with even roots.

However, it is not the case with odd roots. We can find an #x# such that #x*x*x=-8#, the answer is #x=-2#. Therefore the domain is not restricted for odd roots.

In general, for odd roots of positive values will have a positive answer and odd roots of negative values will have a negative answer.