Question

Question #d178e

Answer 1

The space is `99,99mL`.

The amount of molecules of `O_2` and `N_2` in `22.4L`, at the standard pressure and temperature is the number of Avogadro, (that is `6.022xx10^23`).

There are `100mL=0.1L` and so there are

`(6.022xx 10^23)/(22.4/0.1)=(6.022xx10^23)/224=2,69xx10^21`molecules.

The volume of one molecule can be approximated at `3.8xx10^-24 (mL) /("molecule")`, and so the volume of all the molecule is

`V=2,69xx10^21 "molecules"xx3.8xx10^-24 (mL) /("molecule")=0,01`.

And so the answer: the empty space is `99,99mL`.