# Question d178e

Jan 28, 2015

The space is $99 , 99 m L$.

The amount of molecules of ${O}_{2}$ and ${N}_{2}$ in $22.4 L$, at the standard pressure and temperature is the number of Avogadro, (that is $6.022 \times {10}^{23}$).

There are $100 m L = 0.1 L$ and so there are

$\frac{6.022 \times {10}^{23}}{\frac{22.4}{0.1}} = \frac{6.022 \times {10}^{23}}{224} = 2 , 69 \times {10}^{21}$molecules.

The volume of one molecule can be approximated at $3.8 \times {10}^{-} 24 \frac{m L}{\text{molecule}}$, and so the volume of all the molecule is

V=2,69xx10^21 "molecules"xx3.8xx10^-24 (mL) /("molecule")=0,01#.

And so the answer: the empty space is $99 , 99 m L$.