# Question #219fc

Feb 8, 2015

I hope that this is what you are looking for. And I think the proper way of conveying bearing coordinates would be S10E instead of E10S and S22W instead of W22S.

Anyway, the solution:

North-South components , take South as negative and North as positive....

Hence we have:

-50cos(10) + 28cos(55) - 17cos(22)= -48.9m (South)

West-East components , take East as positive and West as negative....

Hence we have:

50sin(10) + 28sin(55) - 17sin(22)= 25.3m (East)

${\left({48.9}^{2} + {25.3}^{2}\right)}^{\frac{1}{2}}$ ....Pythagoras theorem

Final answer is 55m South-East direction.

tan(25.3/48.9)=27.4degrees. Direction is S27.4E

This is the component method which is actually pretty brief. It takes less than 2 minutes.

Just draw, take N-S components and W-E components.