Question

Question #f9c36

Answer 1

There are four free ions on the product side of the equation.

This could be a double displacement reaction of the type

Bi(OCl)₃ + 3CH₃COOH → (CH₃COO)₃Bi + 3HOCl

There will be a reaction if a product is a precipitate, a gas, or a weak electrolyte.

• All acetates are soluble, so (CH₃COO)₃Bi is probably soluble.
• HOCl is a weak electrolyte

Since HOCl is a weak electrolyte, there will be a reaction.

The ionic equation is

Bi(OCl)₃(s) + 3CH₃COOH(aq) → 3CH₃COO⁻(aq) + Bi³⁺(aq) + 3HOCl(aq)

There are four free ions on the product side of the equation.

Here's a video on writing equations with a weak electrolyte (water) as a product.