Question

Question #29a4c

Answer 1

`7.31 xx 10^(-23)` `"g"`

Explanation:

In order to determine the mass of one molecule of `"CO"_2`, the process involves using mole and mass conversion factors to convert from molecules to grams by way of moles.

molecule `->` mole `->` grams

The conversion factors include:

`6.02 xx 10^23` `"molecules = 1 mole" " "` (this is Avogadro's constant)

and

`"1 mole = the molar mass of the molecule"`

The molar mass of carbon dioxide, `"CO"_2`, can be determined by combining the mass of one carbon atom and 2 oxygen atoms.

• `C = 1 xx "12.01 g/mol" = "12.01 g/mol"`
• `O = 2 xx "16.0 g/mol" = "32.0 g/mol"`

So

`"12.01 g/mol + 32.0 g/mol = 44.01 g/mol"`

The conversion is completed as follows:

`1 cancel("molecule CO"_2) xx (1 cancel("mole CO"_2)) / (6.02 xx 10^23 cancel("molecules")) xx "44.01 g"/(1 cancel("mole CO"_2))`

`= 7.31 xx 10^(-23)` `"g CO"_2`

Molecules cancel with molecules and moles cancel with moles
the outcome is the mass in grams.