Question #29a4c

1 Answer

Answer:

#7.31 xx 10^(-23)# #"g"#

Explanation:

In order to determine the mass of one molecule of #"CO"_2#, the process involves using mole and mass conversion factors to convert from molecules to grams by way of moles.

molecule #-># mole #-># grams

The conversion factors include:

#6.02 xx 10^23# #"molecules = 1 mole" " "# (this is Avogadro's constant)

and

#"1 mole = the molar mass of the molecule"#

The molar mass of carbon dioxide, #"CO"_2#, can be determined by combining the mass of one carbon atom and 2 oxygen atoms.

  • #C = 1 xx "12.01 g/mol" = "12.01 g/mol"#
  • #O = 2 xx "16.0 g/mol" = "32.0 g/mol"#

So

#"12.01 g/mol + 32.0 g/mol = 44.01 g/mol"#

The conversion is completed as follows:

#1 cancel("molecule CO"_2) xx (1 cancel("mole CO"_2)) / (6.02 xx 10^23 cancel("molecules")) xx "44.01 g"/(1 cancel("mole CO"_2))#

# = 7.31 xx 10^(-23)# #"g CO"_2#

Molecules cancel with molecules and moles cancel with moles
the outcome is the mass in grams.