Question

Question #68ce1

Answer 1

I think it is 339.6.

This is based on the assumption that you are using the following equation:

`Deltax= v_ot+1/2at^2` (`Deltay` if you're working in the vertical direction).

If this is the case then this is just a simplified version, and you've just moved over the `Deltax` to the other side and set the equation to equal zero. In this case, you can figure that the component next to `t^2` is going to be `a`, or acceleration, the constant will be displacement (`Deltax`), and the component next to `t` must be `v_o`, or initial velocity.

Therefore, your initial velocity is 339.6 (in whatever units pertain to your problem).

Hope that helped :)