# Question #68ce1

Oct 11, 2014

I think it is 339.6.

This is based on the assumption that you are using the following equation:

$\Delta x = {v}_{o} t + \frac{1}{2} a {t}^{2}$ ($\Delta y$ if you're working in the vertical direction).

If this is the case then this is just a simplified version, and you've just moved over the $\Delta x$ to the other side and set the equation to equal zero. In this case, you can figure that the component next to ${t}^{2}$ is going to be $a$, or acceleration, the constant will be displacement ($\Delta x$), and the component next to $t$ must be ${v}_{o}$, or initial velocity.

Therefore, your initial velocity is 339.6 (in whatever units pertain to your problem).

Hope that helped :)