Question #12541

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Answer 1 · 2014-10-10T02:34:37

#y'=2(e^x cosx-e^x sinx)#

In order to find an equation of a line, we will need two pieces of information:

#{("Point: "(x_1,y_1)=(0,2) Rightarrow y"-intercept: "b=2),("Slope: "m=y'(0)=2(e^0 cos(0)-e^0 sin(0))=2):}#

By Slope-Intercept Form #y=mx+b#,

#y=2x+2#.

I hope that this was helpful.