# Question #2b0d7

Let us look at the graph of $y = | x |$ below.
As shown above, $y = | x |$ is differentiable on $\left(- \infty , 0\right) \cup \left(0 , \infty\right)$ since it is just a part of a straight line; however, it is not differentiable at $x = 0$ since there is a sharp corner there.