Question

Question #2b0d7

Answer 1

Remember that differentiability ensures the smoothness of the graph of a function, so if there is a sharp corner in the graph, then the function is not differentiable there.

Let us look at the graph of `y=|x|` below.

As shown above, `y=|x|` is differentiable on `(-infty,0)cup(0,infty)` since it is just a part of a straight line; however, it is not differentiable at `x=0` since there is a sharp corner there.

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I hope that this was helpful.