# Question #753ae

##### 1 Answer

Oct 22, 2014

#F(θ)=(sec(theta)tan(theta))/(1+sec(θ))^2# Explanation :

#F(θ)=sec(θ)/(1+sec(θ))# let's

#y=f(x)/g(x)# Using Quotient Rule,

#y'=(f'(x)g(x)-f(x)g'(x))/(g(x))^2# Similarly following for the given problem and differentiating with respect

#theta# ,

#F(θ)=sec(θ)/(1+sec(θ))#

#F(θ)=((1+sec(θ))(sec(theta)tan(theta))-sec(theta)(sec(theta)tan(theta)))/(1+sec(θ))^2#

#F(θ)=(sec(theta)tan(theta))/(1+sec(θ))^2#