Question #0ffbf

Question

4303 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-11-05T10:14:30

Note that it is a hemisphere, which is a half of a sphere.

Since the volume of a sphere with radius #r# is #4/3pir^3#, the volume #V# of a hemisphere with radius #r# is

#V=1/2cdot4/3pi r^3=2/3pi r^3#,

which gives us the differential

#dV=2pir^2dr#.

Since

#{(dr=0.07 "cm" =0.0007 "m"),(r=50 "m"):}#,

we can approximate

#Delta V approx dV=2pi(50)^2(0.0007)=3.5piapprox 11.00 "cm"^3#

I hope that this was helpful.