Question #19c60

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Answer 1 · 2014-11-08T10:27:05

#sin(330^circ)+cos(315^circ)+tan(45^circ)#

by subtracting #360^circ# from the first two angles,

#=sin(-30^circ)+cos(-45^circ)+tan(45^circ)#

since sine is an odd function, and cosine is an even function,

#=-sin(30^circ)+cos(45^circ)+tan(45^circ)#

by using special triangles,

#=-1/2+sqrt{2}/2+1={1+sqrt{2}}/2#

I hope that this was helpful.