Question #f57de

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Answer 1 · 2014-11-09T14:16:05

I assume that you meant

#lim_{x to infty}[ln(x+1)-lnx]#

by a log property,

#=lim_{x to infty}ln({x+1}/{x})#

by simplifying a bit,

#=lim_{x to infty}ln(1+1/x)#

by putting the limit inside the log,

#=ln[lim_{x to infty}(1+1/x)]=ln(1+0)=ln(1)=0#

I hope that this was helpful.