Question

Question #ceea8

Answer 1

Since you can plug in any real number for `x`, the domain of `f` is

`D_{f} =(-infty, infty)`.

Since `x^2 ge 0`, we have

`f(x)=x^2-2 ge-2`,

which means that the range of `f` is

`R_{f}=[-2, infty)`

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I hope that this was helpful.