Question #f0c8e

Question

Question #f0c8e

1 Answer

Impact of this question

2443 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-12-03T06:54:20

You will need to use the combined gas law in order to answer this question. The combined gas law is represented by the following equation: $P_{1} V_{1} {/T}_{1}$ $"P"_1"V"_1"/T"_1"$ = $P_{2} V_{2} {/T}_{2}$ $"P"_2"V"_2"/T"_2"$ . $STP$ $"STP"$ is $273K$ $"273K"$ and $760.0 mmHg$ $"760.0 mmHg"$ .

Given/Known :
$P_{1}$ $"P"_1$ = $760.0 mmHg$ $"760.0 mmHg"$
$V_{1}$ $"V"_1$ = $125 mL$ $"125 mL"$
$T_{1}$ $"T"_1$ = $273K$ $"273K"$
$P_{2}$ $"P"_2$ = $275 mmHg$ $"275 mmHg"$
$V_{2}$ $"V"_2$ = $425 mL$ $"425 mL"$

Unknown:
$T_{2}$ $"T"_2"$

Equation:
$P_{1} V_{1} {/T}_{1}$ $"P"_1"V"_1"/T"_1"$ = $P_{2} V_{2} {/T}_{2}$ $"P"_2"V"_2"/T"_2"$

Solution: Rearrange the equation to isolate $T_{2}$ $"T"_2$ on one side. Then solve for $T_{2}$ $"T"_2$ .

$T_{2}$ $"T"_2$ = $P_{2} V_{2} T_{1} {/P}_{1} V_{1}$ $"P"_2"V"_2"T"_1"/P"_1"V"_1$
$T_{2}$ $"T"_2$ = $(275 mmHg)(425 mL)(273K)/(760.0 mmHg)(125 mL)$ $"(275 mmHg)(425 mL)(273K)/(760.0 mmHg)(125 mL)"$
$T_{2}$ $"T"_2$ = $336K$ $"336K"$

Convert $T_{2}$ $"T"_2$ from Kelvins to degrees Celsius .
${336K - 273 = 63}^{o} C$ $"336K - 273 = 63"^o"C"$

Science

Math

Humanities

... and beyond

Question #f0c8e

1 Answer

Related questions

Impact of this question