Question #83d0e

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Answer 1 · 2014-12-07T13:01:08

#A(t)=965.1e^{0.016t}#

Since the population is 753 million people, we have

#965.1e^{0.016t}=753#

by dividing by #965.1#,

#=> e^{0.016t}={753}/{965.1}#

by taking the natural log,

#=> 0.016t=ln(753/965.1)#

by dividing by #0.016#,

#=> t={ln(753/965.1)}/0.016 approx -15.5#

Hence, it was #15.5# years before 2003.

I hope that this was helpful.