# Question 82eec

The answer is 14.5%.
Before doing any actual calculations, we could try and estimate the concentration; $44 g$ is close to $\frac{1}{6}$th of the total mass (the mass of the solute - in this case, sugar - plus the mass of the solvent - water - ), so we would expect a concentration of about 16%.
So, c% = m_(solute)/m_(solution) * 100 = (44 g)/((44+259)g) * 100 = 14.5%#, which is close to our initial estimate.