Question #94e1f

1 Answer
Dec 20, 2014

I don't think the question you're asking is possible, because of the inequality theorem of triangles. I've searched online for a similar problem and found this one. I'm guessing you meant that, so here's a summary of the answer:

The answer is #49/4#.
The first thing that's important is that you understand the question. So let's make a drawing:
web.geogebra.org

We're going to add a line, to do this:
web.geogebra.org

The length of #|EB| = 7#, the same as #|AD|#
The length of #|EC| = b-a#

Since the angle of #E# is #90°#, we can apply the Pythagorean theorem:

#(b-a)^2 + 7^2 = (a+b)^2#
If we work this out, we get:
#b^2-2ab+a^2+ 49 = a^2 + 2ab +b^2#
#49 = 4ab#
So, what is the product of #|AB|# and #|CD|#? it's #ab#
#ab = 49/4#

source: maa.org