Question #a9115

1 Answer
Hubert P.
Dec 23, 2014

The derivative is #2/3x + 6/x^3#.

You divide it into sum:
#d/dx(x^2/3) - d/dx(3/x^2) = ...#

The derivative of #x^2# is #2x#. Therefore:
#... = 1/3 * 2x - d/dx(3/x^2)#
Derivative of #1/x^2# is #-3/x^3# which comes from formula for derivative of polynomial function (#d/dx x^n = nx^(n-1)#).

Therefore, the result is #2/3x + 6/x^3#.

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