First, your general chemical reaction looks like this:
CuSO_(4(aq)) + Na_2CO_(3(aq)) -> CuCO_(3(s)) darr + Na_2SO_(4(aq))
Copper(II) sulfate, CuSO_4, and sodium carbonate, Na_2CO_3, are soluble in aqueous solution, which means that they will dissociate into cations and anions.
The reaction produces copper(II) carbonate, CuCO_3, an insoluble solid that precipitates out of solution, and aqueous sodium sulfate, Na_2SO_4.
The complete ionic equation is:
Cu_((aq))^(2+) + SO_(4(aq))^(2-) + 2Na_((aq))^(+) + CO_(3(aq))^(2-) -> CuCO_(3(s)) darr + 2Na_((aq))^(+) + SO_(4(aq))^(2-)
The net ionic equation, which you get after eliminating spectator ions, is:
Cu_((aq))^(2+) + color(red)(cancel(color(black)(SO_(4(aq))^(2-)))) + color(red)(cancel(color(black)(2Na_((aq))^(+)))) + CO_(3(aq))^(2-) -> CuCO_(3(s)) darr + color(red)(cancel(color(black)(2Na_((aq))^(+)))) + color(red)(cancel(color(black)(SO_(4(aq))^(2-))))
Cu_((aq))^(2+) + CO_(3(aq))^(2-) -> CuCO_(3(s)) darr
