# Question 0b93d

Jan 24, 2015

The answer is $\text{260 mL}$.

Usually, a $\text{w/v}$ percent concentration is used for saline solutions, which means that a $\text{0.9%}$ saline solution will have $\text{9 g}$ of $\text{NaCl}$ dissolved in enough water to make $\text{1000 mL}$ of solution.

"w/v" = ("mass solute")/("volume of solution") * 100

So, if you need $\text{9 g}$ to make $\text{1000 mL}$ of solutions, it's clear that less $\text{NaCl}$ will produce less $\text{0.9%}$ solution.

$\text{0.9" = ("2.3 g NaCl")/("V"_("solution")) * 100 => V_("solution") = ("2.3 g" * "100")/"0.9}$

V_("solution") = "256 mL"#, or $\text{260 mL}$ (rounded to two sig figs).