# Question #765f8

##### 2 Answers

The empirial formulae for the 2nd and 3rd compounds are

For the 1st compound:

Ratio by mass X : Z = 1 : 0.472

Ratio by moles = 1/MrX : 0.472/MrZ = 2 :3

This means

So

So

So

For the 2nd compound ratio X : Z by moles =

We can substitute

Ratio by moles =

=

So the mole ratio X : Z = 1 : 1/3 = 3 : 1

So empirical formula is

For the 3rd compound ratio in moles X : Z=

= 1 :4

So the empirical formula is

I don't like this question!

So, you know that you have three reactions that produce three different compounds; however, all three reactions use the same amount of

Here's you generic reaction:

For the first reaction:

Notice that the balanced chemical equation has a

In other words,

This will get you

SInce you'll always have 1.00 g of

In general form,

Let's solve for

This means the second formula is

For

The third formula is