Question

Question #492b7

Answer 1

I would use the Chain Rule having a function, the `sqrt`, of another function, `ln(x)+x`.
I derive the square leaving the argument alone and then I multiply by the derivative of the argument.

Remeber that:
Derivative of `x^n` is `nx^(n-1)`;
`sqrt(x)=x^(1/2)` so the derivative is: `1/2x^(1/2-1)=1/(2sqrt(x))`;
Derivative of `ln(x)` is `1/x`

So for your function you get:
`f'(x)=1/(2sqrt(ln(x)+x))*(1/x+1)`