Question #a4188

1 Answer
Feb 1, 2015

We need to integrate #f(x)=2x+5/\sqrt(1-x^2)#

First of all, the integral of the sum is the sum of the integrals, so we can trade the two addends separately.

The antiderivative of #2x# is easily #2/3 x^3#, given the rule #\int x^n=\frac{x^{n+1}}{n+1}#

As for #\int 1/\sqrt(1-x^2)#, we know that #d/{dx} \sin^{-1}(x) = 1/\sqrt(1-x^2)#, where with #\sin^{-1}(x)# I mean the inverse sine function.

Summing up the two results, the antiderivative is #2/3 x^3+5\sin^{-1}(x)+c#