Question #104b8

1 Answer
Stefan V.
Feb 11, 2015

You would need to add #"0.7"mu"L"# of DNA to your PCR.

This is a basic concentration problem. You know the concentration of your template, which is #"50 ng/"mu"L"#. What this means is that every #"1"mu"L"# of solution will have #"50 ng"# of DNA.

Since you need less than #"50 ng"#, it's obvious that will use less than #"1"mu"L"#

#"35 ng DNA" * ("1"mu"L")/"50 ng DNA" = "0.7"mu"L"#

That is how much volume contains #"35 ng"# of DNA based on the #"50 ng/"mu"L"# template.

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