# Question #3524f

Feb 24, 2015

The first thing to do is rewrite the number of $N i$ atoms in a form that can make the calculations easier. Use scientific notation to help with that

$6 , 000 , 000 , 000 = 6.0 \cdot {10}^{9}$ - six followed by nine zeros.

Next, focus on how many atoms you would get if you had exactly one mole of $N i$. As you know, one mole of $N i$ has $6.022 \cdot {10}^{23}$ atoms of $N i$.

If you compared these two numbers, $6.0 \cdot {10}^{9}$ and $6.022 \cdot {10}^{23}$, it'll be obvious that you have less than 1 mole.

$6.0 \cdot {10}^{9} \text{ atoms of Ni" * ("1 mole of Ni")/(6.022 * 10^(23)"atoms of Ni") ~= 1.0 * 10^(-14)" moles of Ni}$

In other words, $\frac{1}{10} ^ \left(14\right) \text{th}$ of $\text{1 mole of Ni}$ contains $6.0 \cdot {10}^{9}$ atoms of Ni.