Question #fdf1d

1 Answer
Jim H
Mar 6, 2015

For #g(x)=sqrt(5x^2-4x+6)#, the derivative is #g'(x)=1/2(5x^2-4x+6)^(-1/2)(10x-4)#
This answer could also be written: #g'(x)=(5x^2-4x+6)^(-1/2)(5x-2)#
(by distributing the #1/2# through #(10x-4)#)

Perhaps you misread the final answer?

If the final answer you see is #g'(x)=(5x^2-4x+6)^(-1/2)(10x-4)#, then that answer is incorrect.

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