Question #a27d0

1 Answer
Massimiliano
Mar 11, 2015

The answer is: #3x^2y^3-12xy^2+5x^2y^2+c=0#.

#(4xy^3-9y^2+4xy^2)dx+(3x^2y^2-6xy+2x^2y)dy=0rArr#

#(3x^2y^2-6xy+2x^2y)dy=-(4xy^3-9y^2+4xy^2)dxrArr#

#int(3x^2y^2-6xy+2x^2y)dy=-int(4xy^3-9y^2+4xy^2)dxrArr#

#3x^2y^3/3-6xy^2/2+2x^2y^2/2=-4x^2/2y^3+9xy^2-4x^2/2y^2+crArr#

#x^2y^3-3xy^2+x^2y^2+2x^2y^3-9xy^2+2x^2y^2+c=0rArr#

#3x^2y^3-12xy^2+5x^2y^2+c=0#.

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