# Question #9a862

##### 1 Answer

Mar 19, 2015

You would need **b) 5.3 mL** of your stock solution.

The first thing you need to do is figure out how much acrylamide you have in the target **20-mL**, **8%** solution.

Now you need to figure out what volume of the **30%** stock solution contains *that much* acrylamine. Use the same equation as before, only this time solve for the volume of the solution

Watch out for sig figs as well, since you should give the answer with only 1 sig fig, the number of sig figs given for the 20 mL volume.