# Question #32d48

##### 2 Answers

I believe it's appropriate to explain the reasons behind the calculations presented in the first answer.

Let's start from definitions.

**Joule** (abbreviated as *energy* equal to work made by a *force* of 1 newton (

**Watt** (abbreviated as *power* (that is, *energy* per unit of *time*) equal to work of **Joule** (**second** (

Therefore,

or, in words, one **Joule** equals to one **Watt-second**.

Now we have to transform **watt** and **second** into **kilowatt** (**hour** (

Or, reversing this equality,

Using the above equality, we do the calculations presented in the first answer:

As you see, all the difficulties of this problem lie in the definitions of the units of measurement: the two main ones (*energy* and *power*) and a derived unit of **kilowatt-hour**, which is a power of **watt** applied during the time of **hour**.