Question #69048

1 Answer
Jim H
Mar 21, 2015

#sqrt(125/2)=sqrt(125)/sqrt(2)=sqrt(25xx5)/sqrt2=(sqrt(25)xxsqrt(5))/sqrt2=(5sqrt5)/sqrt2#

If "simplify" means you also need to rationalize denominators (it usually does mean this), continue:

#=(5sqrt5)/sqrt2sqrt2/sqrt2=(5sqrt10)/2#

Alternatively:

#sqrt(125/2)=sqrt(125)/sqrt(2)=sqrt(125)/sqrt2sqrt2/sqrt2=sqrt250/2=sqrt(25xx10)/2=(5sqrt10)/2#

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