Question #384cf

1 Answer
Apr 9, 2015

About 0.13 nmol/day

Unless I'm missing something, the rate enhancement is simply the factor by which the rate increases. In this case 10^9 times when the enzyme is added.

So the rate without the enzyme would be (1500 nmols^-1)/10^9

This is equal to 1.5*10^(-6)" nmols"^(-1)

To convert to the desired unit

(1.5*10^(-6) nmol)/s*(3600 s)/(hr) * (24 hr)/(day) = 0.13" nmol/day"