Question

Question #16468

Answer 1

`heat=(1.2/2)*DeltaH_"reaction"`

I am also making some assumptions
1) the reaction is exothermic
2) you know the enthalpy change for the reaction `DeltaH`

The reaction reads 2 moles of A reacts with 3 moles of B to make C. If you know the enthalpy `DeltaH` value for reaction, you would know the joules of heat released for each mole of C produced.

2 moles of A would yield this much heat making 1 mole of C (reacting with excess B).

`heat=("moles of A"/2)*DeltaH_"reaction"`

alternatively

`heat=("moles of B"/3)*DeltaH_"reaction"`

or for moles of C yielded

`heat=("moles of C")*DeltaH_"reaction"`