# Question 16468

Apr 13, 2015

$h e a t = \left(\frac{1.2}{2}\right) \cdot \Delta {H}_{\text{reaction}}$

I am also making some assumptions
1) the reaction is exothermic
2) you know the enthalpy change for the reaction $\Delta H$

The reaction reads 2 moles of A reacts with 3 moles of B to make C. If you know the enthalpy $\Delta H$ value for reaction, you would know the joules of heat released for each mole of C produced.

2 moles of A would yield this much heat making 1 mole of C (reacting with excess B).

heat=("moles of A"/2)*DeltaH_"reaction"

alternatively

heat=("moles of B"/3)*DeltaH_"reaction"

or for moles of C yielded

heat=("moles of C")*DeltaH_"reaction"#