# Question 73a41

Apr 18, 2015

The molarity of your solution will be 2.498 M.

Molarity is defined as moles of solute, in your case sulfuric acid, ${H}_{2} S {O}_{4}$, divided by liters of solution.

You know that the volume of the solution will be 1.000 L, which means that all you have to do is determine how many moles of solfuric acid you get from that mass.

To do that, use the compound's molar mass, which expresses the weight in grams of 1 mole of a substance

245.0cancel("g") * ("1 mole "H_2SO_4)/(98.079cancel("g")) = "2.49798 moles "# ${H}_{2} S {O}_{4}$

This means that the molarity of you solution will be

$C = \frac{n}{V} = \text{2.49798 moles"/"1.000 L" = "2.49798 mol/L}$

Rounded to four sig figs, the answer will be

$C = \textcolor{g r e e n}{\text{2.498 M}}$