Question

Question #d331e

Answer 1

`"a."` Slowly means that the change is an Isothermal change so there is no change in temperature.

`=> P_1V_1=P_2V_2`

`P_1= 1atm` `" , "` `V_2=1/15V_1`

and we are looking for `P_2`

`=>P_2=(P_1V_1)/V_2=(1xxV_1)/(1/15V_1)=15" atm"`

`"b."` Suddenly means that the change is adiabatic. No heat supplied to the system(air)

`=>P_1(V_1)^(gamma)=P_2(V_2)^(gamma)`

`=>P_2=(P_1(V_1)^(gamma))/(V_2)^(gamma)`

`=>P_2=(1xx(V_1)^(gamma))/(1/15V_1)^(gamma)`

`=>P_2=(V_1)^(1.4)/((1/15)^(1.4)xx(V_1)^(1.4))=15^1.4=44.3" atm"`