# Question b6669

Apr 30, 2015

The new volume of hydrogen gas at STP is $4550 \text{L}$.

The equation for the combined gas law is $\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$.

If I read your problem correctly, you want the volume of hydrogen gas after it has been adjusted to STP.

Known:
${P}_{1} = 100.0 \text{atm}$
${V}_{1} = 50.0 \text{amt}$
${T}_{1} = {27.0}^{\text{o""C+273.15=300.2K}}$

${P}_{2} = 1.00 \text{atm}$
${T}_{2} = {0}^{\text{o""C+273.15=273.15K}}$

Unknown:
${V}_{2}$

Solution: Rearrange the equation to isolate and solve for ${V}_{2}$.

V_2=(P_1V_1T_2)/(T_1P_2)=(100.0cancel"atm" * 50.0 "L" * 273.15cancel"K")/(300.2cancel"K" * 1.00cancel"atm")=4550 "L"#