Question #709ad

1 Answer
May 14, 2015

Considering your function as: #f(x)=-2sin(pi/2x)# (I think), you have:

1] The Period of your function (basically the length of an entire oscillation) is: #(period)=(2pi)/color(red)(pi/2)=4# (using the #pi/2# which is multiplying #x# in the argument of #sin#);
2] The Frequency #f# of your function (basically the number of complete oscillations in one unit length) is equal to #1/(period)# so that: #f=1/4#, meaning that in 1 unit length you have #1/4# complete oscillation.

Graphically:
graph{-2sin(pix/2) [-7.023, 7.024, -3.51, 3.513]}
As you can see an entire complete oscillation goes, for example, from #0# to #4# (Period) and from #0# to #1# (one unit length) you have only #1/4# of an oscillation.

Hope it helps!