Question #536ac

1 Answer
Michael
May 20, 2015

86.8kJ

1 mole requires 40.5 kJ

#M_r= (12xx2) +(5xx1) +16 + 1)=46#

Approx Ar values used so I'll say I mole weighs 46.0g.

You should use the values you are given and quote the significant figures accordingly.

So:

46.0g requires 40.5kJ

1g requires 40.5/46.0 kJ

98.6g requires (40.5/46.0) x 98.6 = 86.8g

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