# Question #7ab5e

##### 1 Answer

After six hours, the box will contain **3.7 kg** of ice.

Here's what the idea behind this problem is. Since the problem provided the *enthalpy of fusion* of ice, you know that the temperature inside the box is

Because the outside of the box is at a *higher* temperature, heat will flow **from** the room and **into** the box via *conduction*. This will cause the ice to undergo a phase change, i.e. a certain amount of ice will melt.

This means that the heat that flows into the box will be *equal* to the heat absorbed by ice.

The heat transferred by conduction can be written like this

**6 h**;

*thermal conductivity* of the material, in your case

Since you'r edealing with a cubic box, the *total* area will be

Plug your values into this equation to determine how much heat flows into the box in six hours, but keep in mind that you need to convert hours to seconds and centimeters to meters.

Since this will be equal to the heat absorbed by the ice, you can use it to determine how much ice *melted*

This means that you'll be left with

**SIDE NOTE** *I used two sig figs for the answer, despite the fact that your values require only one sig fig.*

*In this case, using one sig fig would imply that all the ice remained unmelted.*