Question #bcb2d
1 Answer
Jun 5, 2015
calculate moles of Acid, calculate moles of Base. subtract,
LxM=moles 0.050L x 0.200M NaOH = 0.0100mol
0.030L x 0.200M
0.0100mol of
M=mol/L
0.004mol/0.080L
= 0.050M of
pOH = -log(0.05) = 1.30, 14-1.30= 12.70