Question #4a8a4

Jun 16, 2015

Let's call the first terms ${x}_{1} , {x}_{2} , {x}_{3}$

Explanation:

Then the sum of the first two terms is:
${x}_{1} + {x}_{2} = {x}_{1} + \left({x}_{1} + 6\right) = 24 \to$
$2 \cdot {x}_{1} = 18 \to {x}_{1} = 9$

Then ${x}_{2} = {x}_{1} + 6 = 9 + 6 = 15$
And ${x}_{3} = {x}_{2} + 9 = 15 + 9 = 24$
And so on.