You need 8 g of sodium chloride to make that solution.
Since you know what the volume and the molarity of the target solution have to be, you can determine how many moles of sodium chloride you'd need by
Notice that I converted the volume from mL to L. In addition to that, I used the fact that
Now use sodium chloride's molar mass, which tells you what the mass of 1 mole of sodium chloride is, to determine how many grams would contain that many moles.
Rounded to one sig fig, the number of sig figs you gave for the volume and molarity of the solution, the answer will be
So, in order to make this solution, you add 8 g of