# Question #ade43

##### 1 Answer

#### Explanation:

So, you know that **20 g** of your *sparingly soluble* salt, **40. g/mol**, is dissolved in one liter of water.

This means that you can determine its *molar solubility*, i.e. the number of moles of salt that can *actually* be dissolved in one liter of water. Start by figuring out how many moles of salt you have

This means that its *molar solubility* will be

In order to be able to calculate its *solubility product constant*, you need to determine how many moles of

Use an **ICE table** to help you with that

**I**.......

**C**.....

**E**.....

By definition, the solubility product constant,

*molar solubility* of the salt.

Since you know that you can dissolve **0.5 moles** in one liter of water,

This means that

The answer is rounded to one sig fig, the number of sig figs you gave for the mass of the salt.