Question #11471

Jun 17, 2015

The solution that contains 12 g of sucrose in 15 g of water.

Explanation:

You can determine how concentrated a solution is by determining its percent concentration by mass, $\text{%w/w}$.

Percent concentration by mass is defined as mass of solute, in your case sucrose, or common sugar, divided by the total mass of the solution and multiplied by 100.

This means that the two solutions will be

$\text{%w/w" = (80cancel("g"))/((80 + 120)cancel("g")) * 100 = "40% w/w}$ $\to$ solution 1.

$\text{%w/w" = (12cancel("g"))/((12 + 15)cancel("g")) * 100 = "44.4% w/w}$ $\to$ solution 2.

This means that the second solution has more sucrose per 100 g than the first solution. More specifically, you get

• 40 g sucrose for every 100 g solution $\to$ solution 1;
• 44.4 g sucrose for every 100 g solution $\to$ solution 2.

Therefore, solution 2 is more concentrated.