# Question a4bc2

Jun 24, 2015

I found $500 N$

#### Explanation:

Considering that the weight of the astronaut is given as:
$W = 700 N = {m}_{a} \cdot g = {m}_{a} \cdot \left[G \cdot {m}_{e a r t h} / {R}_{e a r t h}^{2}\right]$ where:
$G$ is the Universal Gravitational Constant:
${R}_{e a r t h}$ is the earth's radius;
${m}_{e a r t h}$ is the earth's mass.

Now if we use the data for the other planet we get:
$m = 3 {m}_{e a r t h}$
$R = 2 {R}_{e a r t h}$
W=m_a*g_(?)=m_a*[G*(3m_(earth))/(4R_(earth)^2)]#
so:
${m}_{a} \cdot \left[G \cdot {m}_{e a r t h} / {R}^{2}\right] \cdot \frac{3}{4} = \frac{3}{4} \cdot 700 = 525 \approx 500 N$